Formulate the quadratic function that contains the points (-1,2), (0,-1) and (2,5). 1.) f(x) = 2x^2 + x + 1 2.) f(x) = 2x^2 - x - 1 3.) f(x) = 2x^2 - x + 2 4.) f(x) = 2x^2 - x - 2

Answer:option 2 2x²- x - 1 Step-by-step explanation:We are given points: (-1,2), (0,-1) and (2,5)Substitute each point one by one in the quadratic equation to check if the quadratic equation contains all points mention.2) f(x) = 2x²- x - 1    Point(-1,2)    f(-1) = 2(-1)² -(-1) -1    2 = 2 + 1 - 1    2 = 2   Point(0,-1)    f(0) = 2(0)² -(0) -1    -1 = 0 - 0 -1    -1 = -1   Point(2,5)   f(2) = 2(2)² -(2) -1   5 = 8 - 2 -1   5 = 6 - 1   5 = 5